Base | Representation |
---|---|
bin | 1011100101101110… |
… | …0100101111000000 |
3 | 22000210220211222021 |
4 | 2321123210233000 |
5 | 22332404411222 |
6 | 1232411451224 |
7 | 140044114441 |
oct | 27133445700 |
9 | 8023824867 |
10 | 3111013312 |
11 | 13570a4390 |
12 | 729a56b14 |
13 | 3a76b2ba4 |
14 | 2172632c8 |
15 | 1331c1ac7 |
hex | b96e4bc0 |
3111013312 has 56 divisors (see below), whose sum is σ = 6801471792. Its totient is φ = 1400064000.
The previous prime is 3111013303. The next prime is 3111013313. The reversal of 3111013312 is 2133101113.
3111013312 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (16).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3111013313) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 49228 + ... + 92980.
Almost surely, 23111013312 is an apocalyptic number.
3111013312 is a gapful number since it is divisible by the number (32) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 3111013312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3400735896).
3111013312 is an abundant number, since it is smaller than the sum of its proper divisors (3690458480).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3111013312 is a wasteful number, since it uses less digits than its factorization.
3111013312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43877 (or 43867 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 16.
The square root of 3111013312 is about 55776.4584031650. The cubic root of 3111013312 is about 1459.8244162400.
Adding to 3111013312 its reverse (2133101113), we get a palindrome (5244114425).
It can be divided in two parts, 311101 and 3312, that added together give a palindrome (314413).
The spelling of 3111013312 in words is "three billion, one hundred eleven million, thirteen thousand, three hundred twelve".
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