Base | Representation |
---|---|
bin | 1110001001011111000000… |
… | …11010010100100001100000 |
3 | 11002011022001121220100210010 |
4 | 13010233200122110201200 |
5 | 13034220303024333440 |
6 | 150100430422204520 |
7 | 6360532434053655 |
oct | 704574032244140 |
9 | 132138047810703 |
10 | 31112213121120 |
11 | 9a0568523877a |
12 | 35a5909283740 |
13 | 1448b3b57b6c1 |
14 | 797ba68abc2c |
15 | 38e477a97580 |
hex | 1c4be0694860 |
31112213121120 has 48 divisors (see below), whose sum is σ = 98003471333040. Its totient is φ = 8296590165504.
The previous prime is 31112213121091. The next prime is 31112213121163. The reversal of 31112213121120 is 2112131221113.
It is a tau number, because it is divible by the number of its divisors (48).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 32408554855 + ... + 32408555814.
It is an arithmetic number, because the mean of its divisors is an integer number (2041738986105).
Almost surely, 231112213121120 is an apocalyptic number.
31112213121120 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
31112213121120 is an abundant number, since it is smaller than the sum of its proper divisors (66891258211920).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31112213121120 is a wasteful number, since it uses less digits than its factorization.
31112213121120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 64817110687 (or 64817110679 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 21.
Adding to 31112213121120 its reverse (2112131221113), we get a palindrome (33224344342233).
The spelling of 31112213121120 in words is "thirty-one trillion, one hundred twelve billion, two hundred thirteen million, one hundred twenty-one thousand, one hundred twenty".
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