Base | Representation |
---|---|
bin | 1001000100000011100… |
… | …01111111101100000100 |
3 | 1002202211001021201120001 |
4 | 10202001301333230010 |
5 | 20100234220341400 |
6 | 355021224251044 |
7 | 31333103633113 |
oct | 4420161775404 |
9 | 1082731251501 |
10 | 311415012100 |
11 | 1100857238a5 |
12 | 50430310a84 |
13 | 2349ba2283a |
14 | 111031a3c7a |
15 | 81798c9a6a |
hex | 4881c7fb04 |
311415012100 has 72 divisors (see below), whose sum is σ = 695304435168. Its totient is φ = 120992083200.
The previous prime is 311415012089. The next prime is 311415012121. The reversal of 311415012100 is 1210514113.
It is a super-2 number, since 2×3114150121002 (a number of 24 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 763399 + ... + 1098001.
It is an arithmetic number, because the mean of its divisors is an integer number (9657006044).
Almost surely, 2311415012100 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 311415012100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (347652217584).
311415012100 is an abundant number, since it is smaller than the sum of its proper divisors (383889423068).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
311415012100 is a wasteful number, since it uses less digits than its factorization.
311415012100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 334885 (or 334878 counting only the distinct ones).
The product of its (nonzero) digits is 120, while the sum is 19.
Adding to 311415012100 its reverse (1210514113), we get a palindrome (312625526213).
It can be divided in two parts, 3114150 and 12100, that added together give a triangular number (3126250 = T2500).
The spelling of 311415012100 in words is "three hundred eleven billion, four hundred fifteen million, twelve thousand, one hundred".
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