311431323404040 has 96 divisors (see below), whose sum is σ = 1086831761287680. Its totient is φ = 71184302491008.

The previous prime is 311431323404029. The next prime is 311431323404059. The reversal of 311431323404040 is 40404323134113.

It is a junction number, because it is equal to n+sod(n) for n = 311431323403992 and 311431323404010.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 26482249512 + ... + 26482261271.

It is an arithmetic number, because the mean of its divisors is an integer number (11321164180080).

Almost surely, 2^{311431323404040} is an apocalyptic number.

311431323404040 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

311431323404040 is an abundant number, since it is smaller than the sum of its proper divisors (775400437883640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

311431323404040 is a wasteful number, since it uses less digits than its factorization.

311431323404040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 52964510811 (or 52964510800 counting only the distinct ones).

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 311431323404040 its reverse (40404323134113), we get a palindrome (351835646538153).

The spelling of 311431323404040 in words is "three hundred eleven trillion, four hundred thirty-one billion, three hundred twenty-three million, four hundred four thousand, forty".