Base | Representation |
---|---|
bin | 101101011011110111101… |
… | …110011011011110010000 |
3 | 102001111012121210221112110 |
4 | 231123313232123132100 |
5 | 402123433403303100 |
6 | 10350211012225320 |
7 | 441402364336101 |
oct | 55336756333620 |
9 | 12044177727473 |
10 | 3122302400400 |
11 | aa4185341347 |
12 | 42515890b240 |
13 | 19857ca1cb71 |
14 | ab197d343a8 |
15 | 563418e2250 |
hex | 2d6f7b9b790 |
3122302400400 has 120 divisors (see below), whose sum is σ = 10002311936064. Its totient is φ = 832569305600.
The previous prime is 3122302400387. The next prime is 3122302400443. The reversal of 3122302400400 is 40042032213.
It is a tau number, because it is divible by the number of its divisors (120).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 26529685 + ... + 26647115.
Almost surely, 23122302400400 is an apocalyptic number.
3122302400400 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
3122302400400 is an abundant number, since it is smaller than the sum of its proper divisors (6880009535664).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3122302400400 is a wasteful number, since it uses less digits than its factorization.
3122302400400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 139609 (or 139598 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 21.
Adding to 3122302400400 its reverse (40042032213), we get a palindrome (3162344432613).
The spelling of 3122302400400 in words is "three trillion, one hundred twenty-two billion, three hundred two million, four hundred thousand, four hundred".
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