Base | Representation |
---|---|
bin | 100011100110000110100111… |
… | …0010010100100010100010100 |
3 | 1112001121002011200222202022020 |
4 | 1013030031032102210110110 |
5 | 312014313033401320200 |
6 | 3025524114400333140 |
7 | 122643511131561501 |
oct | 10714151622442424 |
9 | 1461532150882266 |
10 | 313100134401300 |
11 | 90844026402a74 |
12 | 2b148aa16141b0 |
13 | 105922a669985c |
14 | 57461ad6a64a8 |
15 | 262e6bde2cea0 |
hex | 11cc34e4a4514 |
313100134401300 has 72 divisors (see below), whose sum is σ = 905923517038176. Its totient is φ = 83491483320960.
The previous prime is 313100134401163. The next prime is 313100134401323. The reversal of 313100134401300 is 3104431001313.
It is a super-3 number, since 3×3131001344013003 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1542699 + ... + 25071501.
Almost surely, 2313100134401300 is an apocalyptic number.
313100134401300 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
313100134401300 is an abundant number, since it is smaller than the sum of its proper divisors (592823382636876).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
313100134401300 is a wasteful number, since it uses less digits than its factorization.
313100134401300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23573177 (or 23573170 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 313100134401300 its reverse (3104431001313), we get a palindrome (316204565402613).
The spelling of 313100134401300 in words is "three hundred thirteen trillion, one hundred billion, one hundred thirty-four million, four hundred one thousand, three hundred".
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