Base | Representation |
---|---|
bin | 101101110000010111100… |
… | …010101111110110011111 |
3 | 102010121000102221221220110 |
4 | 231300113202233312133 |
5 | 403004022111424120 |
6 | 10404250534021103 |
7 | 443111646622212 |
oct | 55602742576637 |
9 | 12117012857813 |
10 | 3144311045535 |
11 | 1002549682170 |
12 | 42947b4a7793 |
13 | 19a6795aaaca |
14 | ac284cc5779 |
15 | 56bcdb7c2e0 |
hex | 2dc178afd9f |
3144311045535 has 64 divisors (see below), whose sum is σ = 5572786143744. Its totient is φ = 1501054156800.
The previous prime is 3144311045489. The next prime is 3144311045537. The reversal of 3144311045535 is 5355401134413.
3144311045535 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3144311045535 - 229 = 3143774174623 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3144311045493 and 3144311045502.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3144311045537) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 23824047 + ... + 23955663.
It is an arithmetic number, because the mean of its divisors is an integer number (87074783496).
Almost surely, 23144311045535 is an apocalyptic number.
3144311045535 is a deficient number, since it is larger than the sum of its proper divisors (2428475098209).
3144311045535 is a wasteful number, since it uses less digits than its factorization.
3144311045535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 133864.
The product of its (nonzero) digits is 216000, while the sum is 39.
Adding to 3144311045535 its reverse (5355401134413), we get a palindrome (8499712179948).
The spelling of 3144311045535 in words is "three trillion, one hundred forty-four billion, three hundred eleven million, forty-five thousand, five hundred thirty-five".
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