Base | Representation |
---|---|
bin | 1001001010111110101… |
… | …01101011001011010000 |
3 | 1010010102002200212201101 |
4 | 10211133111223023100 |
5 | 20130342311130000 |
6 | 400434131114144 |
7 | 31524160623412 |
oct | 4453725531320 |
9 | 1103362625641 |
10 | 315132130000 |
11 | 111712965566 |
12 | 510a9142954 |
13 | 23941b5aa9c |
14 | 11376b1c9b2 |
15 | 82e5dc2e6a |
hex | 495f56b2d0 |
315132130000 has 50 divisors (see below), whose sum is σ = 762966424154. Its totient is φ = 126052848000.
The previous prime is 315132129997. The next prime is 315132130043. The reversal of 315132130000 is 31231513.
It can be written as a sum of positive squares in 5 ways, for example, as 214843374144 + 100288755856 = 463512^2 + 316684^2 .
It is a tau number, because it is divible by the number of its divisors (50).
It is a self number, because there is not a number n which added to its sum of digits gives 315132130000.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 15746607 + ... + 15766606.
Almost surely, 2315132130000 is an apocalyptic number.
It is an amenable number.
315132130000 is an abundant number, since it is smaller than the sum of its proper divisors (447834294154).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
315132130000 is an equidigital number, since it uses as much as digits as its factorization.
315132130000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31513241 (or 31513220 counting only the distinct ones).
The product of its (nonzero) digits is 270, while the sum is 19.
Adding to 315132130000 its reverse (31231513), we get a palindrome (315163361513).
The spelling of 315132130000 in words is "three hundred fifteen billion, one hundred thirty-two million, one hundred thirty thousand".
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