Base | Representation |
---|---|
bin | 1110011000110110010110… |
… | …00000110111101111011110 |
3 | 11011000202201102020211212100 |
4 | 13030123023000313233132 |
5 | 13121342444041334002 |
6 | 151143135530345530 |
7 | 6443632020640530 |
oct | 714331300675736 |
9 | 134022642224770 |
10 | 31640135105502 |
11 | a099562457320 |
12 | 36700a128b2a6 |
13 | 1486862400111 |
14 | 7b5568173850 |
15 | 39d074b8111c |
hex | 1cc6cb037bde |
31640135105502 has 48 divisors (see below), whose sum is σ = 85469455873152. Its totient is φ = 8218216910160.
The previous prime is 31640135105479. The next prime is 31640135105531. The reversal of 31640135105502 is 20550153104613.
31640135105502 is a `hidden beast` number, since 3 + 1 + 6 + 4 + 0 + 135 + 10 + 5 + 502 = 666.
It is a super-3 number, since 3×316401351055023 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 11414188768 + ... + 11414191539.
It is an arithmetic number, because the mean of its divisors is an integer number (1780613664024).
Almost surely, 231640135105502 is an apocalyptic number.
31640135105502 is an abundant number, since it is smaller than the sum of its proper divisors (53829320767650).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31640135105502 is a wasteful number, since it uses less digits than its factorization.
31640135105502 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22828380333 (or 22828380330 counting only the distinct ones).
The product of its (nonzero) digits is 54000, while the sum is 36.
The spelling of 31640135105502 in words is "thirty-one trillion, six hundred forty billion, one hundred thirty-five million, one hundred five thousand, five hundred two".
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