32540401350 has 120 divisors (see below), whose sum is σ = 90515080920. Its totient is φ = 8667751680.

The previous prime is 32540401349. The next prime is 32540401351. The reversal of 32540401350 is 5310404523.

32540401350 is a `hidden beast` number, since 3 + 254 + 0 + 401 + 3 + 5 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (32540401349) and next prime (32540401351).

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (32540401351) by changing a digit.

It is a polite number, since it can be written in 59 ways as a sum of consecutive naturals, for example, 4082469 + ... + 4090431.

It is an arithmetic number, because the mean of its divisors is an integer number (754292341).

Almost surely, 2^32540401350 is an apocalyptic number.

32540401350 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 32540401350, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (45257540460).

32540401350 is an abundant number, since it is smaller than the sum of its proper divisors (57974679570).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

32540401350 is a wasteful number, since it uses less digits than its factorization.

32540401350 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8996 (or 8982 counting only the distinct ones).

The product of its (nonzero) digits is 7200, while the sum is 27.

Adding to 32540401350 its reverse (5310404523), we get a palindrome (37850805873).

The spelling of 32540401350 in words is "thirty-two billion, five hundred forty million, four hundred one thousand, three hundred fifty".