Base | Representation |
---|---|
bin | 1111000011011000000000… |
… | …00000100100100011100000 |
3 | 11100012110021102102202202021 |
4 | 13201230000000210203200 |
5 | 13314312442123200000 |
6 | 154222311110031224 |
7 | 6654330252652555 |
oct | 741540000444340 |
9 | 140173242382667 |
10 | 33101313100000 |
11 | a602208328342 |
12 | 386730a948514 |
13 | 1561595822422 |
14 | 82617d874a2c |
15 | 3c6093b8411a |
hex | 1e1b000248e0 |
33101313100000 has 144 divisors (see below), whose sum is σ = 83441768103792. Its totient is φ = 12917584000000.
The previous prime is 33101313099983. The next prime is 33101313100003. The reversal of 33101313100000 is 131310133.
It is a super-2 number, since 2×331013131000002 (a number of 28 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (16).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (33101313100003) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 63255 + ... + 8136745.
It is an arithmetic number, because the mean of its divisors is an integer number (579456722943).
Almost surely, 233101313100000 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 33101313100000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (41720884051896).
33101313100000 is an abundant number, since it is smaller than the sum of its proper divisors (50340455003792).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
33101313100000 is an frugal number, since it uses more digits than its factorization.
33101313100000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8073567 (or 8073539 counting only the distinct ones).
The product of its (nonzero) digits is 81, while the sum is 16.
Adding to 33101313100000 its reverse (131310133), we get a palindrome (33101444410133).
The spelling of 33101313100000 in words is "thirty-three trillion, one hundred one billion, three hundred thirteen million, one hundred thousand".
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