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333200101013130 = 235133723090790091
BaseRepresentation
bin100101111000010110011000…
…1101010001111011010001010
31121200202121200221021022020210
41023300230301222033122022
5322133122301324410010
63140354002510101550
7130116625056032331
oct11360546152173212
91550677627238223
10333200101013130
119719340757107a
12314544b37aa8b6
13113bc83359cac0
145c3cd84372d18
15287c475105b20
hex12f0b31a8f68a

333200101013130 has 64 divisors (see below), whose sum is σ = 884469623683968. Its totient is φ = 79801770551040.

The previous prime is 333200101013123. The next prime is 333200101013137. The reversal of 333200101013130 is 31310101002333.

It is an interprime number because it is at equal distance from previous prime (333200101013123) and next prime (333200101013137).

It is a super-2 number, since 2×3332001010131302 (a number of 30 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 333200101013097 and 333200101013106.

It is not an unprimeable number, because it can be changed into a prime (333200101013137) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 11545380616 + ... + 11545409475.

It is an arithmetic number, because the mean of its divisors is an integer number (13819837870062).

Almost surely, 2333200101013130 is an apocalyptic number.

333200101013130 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

333200101013130 is an abundant number, since it is smaller than the sum of its proper divisors (551269522670838).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

333200101013130 is a wasteful number, since it uses less digits than its factorization.

333200101013130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23090790151.

The product of its (nonzero) digits is 486, while the sum is 21.

Adding to 333200101013130 its reverse (31310101002333), we get a palindrome (364510202015463).

The spelling of 333200101013130 in words is "three hundred thirty-three trillion, two hundred billion, one hundred one million, thirteen thousand, one hundred thirty".

Divisors: 1 2 3 5 6 10 13 15 26 30 37 39 65 74 78 111 130 185 195 222 370 390 481 555 962 1110 1443 2405 2886 4810 7215 14430 23090790091 46181580182 69272370273 115453950455 138544740546 230907900910 300180271183 346361851365 600360542366 692723702730 854359233367 900540813549 1500901355915 1708718466734 1801081627098 2563077700101 3001802711830 4271796166835 4502704067745 5126155400202 8543592333670 9005408135490 11106670033771 12815388500505 22213340067542 25630777001010 33320010101313 55533350168855 66640020202626 111066700337710 166600050506565 333200101013130