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34200120120 = 23358315721871
BaseRepresentation
bin11111110110011111…
…000110101100111000
310021021110120010000120
4133312133012230320
51030020212320440
623413351133240
72320340140005
oct376637065470
9107243503016
1034200120120
1113560092491
126765674220
1332c05b368a
1419261b28ac
15d5272ddd0
hex7f67c6b38

34200120120 has 128 divisors (see below), whose sum is σ = 104502666240. Its totient is φ = 8952353280.

The previous prime is 34200120091. The next prime is 34200120121. The reversal of 34200120120 is 2102100243.

It is a Harshad number since it is a multiple of its sum of digits (15).

34200120120 is a modest number, since divided by 120120 gives 34200 as remainder.

It is a self number, because there is not a number n which added to its sum of digits gives 34200120120.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (34200120121) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1552785 + ... + 1574655.

It is an arithmetic number, because the mean of its divisors is an integer number (816427080).

Almost surely, 234200120120 is an apocalyptic number.

34200120120 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 34200120120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (52251333120).

34200120120 is an abundant number, since it is smaller than the sum of its proper divisors (70302546120).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

34200120120 is a wasteful number, since it uses less digits than its factorization.

34200120120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22125 (or 22121 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 15.

Adding to 34200120120 its reverse (2102100243), we get a palindrome (36302220363).

The spelling of 34200120120 in words is "thirty-four billion, two hundred million, one hundred twenty thousand, one hundred twenty".

Divisors: 1 2 3 4 5 6 8 10 12 15 20 24 30 40 60 83 120 157 166 249 314 332 415 471 498 628 664 785 830 942 996 1245 1256 1570 1660 1884 1992 2355 2490 3140 3320 3768 4710 4980 6280 9420 9960 13031 18840 21871 26062 39093 43742 52124 65155 65613 78186 87484 104248 109355 130310 131226 156372 174968 195465 218710 260620 262452 312744 328065 390930 437420 521240 524904 656130 781860 874840 1312260 1563720 1815293 2624520 3433747 3630586 5445879 6867494 7261172 9076465 10301241 10891758 13734988 14522344 17168735 18152930 20602482 21783516 27229395 27469976 34337470 36305860 41204964 43567032 51506205 54458790 68674940 72611720 82409928 103012410 108917580 137349880 206024820 217835160 285001001 412049640 570002002 855003003 1140004004 1425005005 1710006006 2280008008 2850010010 3420012012 4275015015 5700020020 6840024024 8550030030 11400040040 17100060060 34200120120