3483113700 has 72 divisors (see below), whose sum is σ = 10993983840. Its totient is φ = 844390400.

The previous prime is 3483113677. The next prime is 3483113723. The reversal of 3483113700 is 73113843.

3483113700 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (3483113677) and next prime (3483113723).

It is a Harshad number since it is a multiple of its sum of digits (30).

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 524445 + ... + 531044.

It is an arithmetic number, because the mean of its divisors is an integer number (152694220).

Almost surely, 2^3483113700 is an apocalyptic number.

3483113700 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

3483113700 is an abundant number, since it is smaller than the sum of its proper divisors (7510870140).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3483113700 is a wasteful number, since it uses less digits than its factorization.

3483113700 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1055517 (or 1055510 counting only the distinct ones).

The product of its (nonzero) digits is 6048, while the sum is 30.

The square root of 3483113700 is about 59017.9099934927. The cubic root of 3483113700 is about 1515.8487983972.

The spelling of 3483113700 in words is "three billion, four hundred eighty-three million, one hundred thirteen thousand, seven hundred".