3983749862400 has 4752 divisors, whose sum is σ = 20254316944320. Its totient is φ = 758041804800.

The previous prime is 3983749862377. The next prime is 3983749862423. The reversal of 3983749862400 is 42689473893.

3983749862400 is a `hidden beast` number, since 3 + 9 + 83 + 7 + 4 + 98 + 62 + 400 = 666.

It is an interprime number because it is at equal distance from previous prime (3983749862377) and next prime (3983749862423).

It is a tau number, because it is divible by the number of its divisors (4752).

It is a Harshad number since it is a multiple of its sum of digits (63).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 431 ways as a sum of consecutive naturals, for example, 107668915182 + ... + 107668915218.

Almost surely, 2^{3983749862400} is an apocalyptic number.

3983749862400 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 3983749862400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (10127158472160).

3983749862400 is an abundant number, since it is smaller than the sum of its proper divisors (16270567081920).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3983749862400 is a wasteful number, since it uses less digits than its factorization.

3983749862400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 135 (or 82 counting only the distinct ones).

The product of its (nonzero) digits is 62705664, while the sum is 63.

The spelling of 3983749862400 in words is "three trillion, nine hundred eighty-three billion, seven hundred forty-nine million, eight hundred sixty-two thousand, four hundred".