Base | Representation |
---|---|
bin | 100110010010011111… |
… | …101111110000000111 |
3 | 10221010012102110022200 |
4 | 212102133233300013 |
5 | 1133144300020010 |
6 | 30515315325543 |
7 | 2653543331460 |
oct | 462237576007 |
9 | 127105373280 |
10 | 41112501255 |
11 | 16487a31771 |
12 | 7b745b08b3 |
13 | 3b526bc427 |
14 | 1dc0241d67 |
15 | 11094dbcc0 |
hex | 9927efc07 |
41112501255 has 24 divisors (see below), whose sum is σ = 81441907872. Its totient is φ = 18794286144.
The previous prime is 41112501251. The next prime is 41112501281. The reversal of 41112501255 is 55210521114.
It is a happy number.
41112501255 is a `hidden beast` number, since 41 + 112 + 501 + 2 + 5 + 5 = 666.
It is not a de Polignac number, because 41112501255 - 22 = 41112501251 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (41112501251) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 65257624 + ... + 65258253.
It is an arithmetic number, because the mean of its divisors is an integer number (3393412828).
Almost surely, 241112501255 is an apocalyptic number.
41112501255 is a gapful number since it is divisible by the number (45) formed by its first and last digit.
41112501255 is a deficient number, since it is larger than the sum of its proper divisors (40329406617).
41112501255 is a wasteful number, since it uses less digits than its factorization.
41112501255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 130515895 (or 130515892 counting only the distinct ones).
The product of its (nonzero) digits is 2000, while the sum is 27.
The spelling of 41112501255 in words is "forty-one billion, one hundred twelve million, five hundred one thousand, two hundred fifty-five".
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