Base | Representation |
---|---|
bin | 111011110110101000100… |
… | …010000101111111110111 |
3 | 112120012122210101121212011 |
4 | 323312220202011333313 |
5 | 1014342122432241043 |
6 | 12425312011505051 |
7 | 603106505306422 |
oct | 73665042057767 |
9 | 15505583347764 |
10 | 4113111212023 |
11 | 13463a7061390 |
12 | 565194758187 |
13 | 23ab31a47aa8 |
14 | 10310b7d89b9 |
15 | 71ed12b359d |
hex | 3bda8885ff7 |
4113111212023 has 4 divisors (see below), whose sum is σ = 4487030413128. Its totient is φ = 3739192010920.
The previous prime is 4113111211969. The next prime is 4113111212033. The reversal of 4113111212023 is 3202121113114.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4113111212023 - 29 = 4113111211511 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 4113111211985 and 4113111212003.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4113111212033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 186959600536 + ... + 186959600557.
It is an arithmetic number, because the mean of its divisors is an integer number (1121757603282).
Almost surely, 24113111212023 is an apocalyptic number.
4113111212023 is a deficient number, since it is larger than the sum of its proper divisors (373919201105).
4113111212023 is a wasteful number, since it uses less digits than its factorization.
4113111212023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 373919201104.
The product of its (nonzero) digits is 288, while the sum is 22.
Adding to 4113111212023 its reverse (3202121113114), we get a palindrome (7315232325137).
The spelling of 4113111212023 in words is "four trillion, one hundred thirteen billion, one hundred eleven million, two hundred twelve thousand, twenty-three".
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