Base | Representation |
---|---|
bin | 111011111101001100000… |
… | …110100110001000011111 |
3 | 112120212211100221011112122 |
4 | 323331030012212020133 |
5 | 1020001032002344320 |
6 | 12432434310453155 |
7 | 603446111564435 |
oct | 73751406461037 |
9 | 15525740834478 |
10 | 4120150434335 |
11 | 1349389565291 |
12 | 56661a0641bb |
13 | 23b6b42045b0 |
14 | 1035b8644d55 |
15 | 72294278d25 |
hex | 3bf4c1a621f |
4120150434335 has 64 divisors (see below), whose sum is σ = 5656423207680. Its totient is φ = 2854107586560.
The previous prime is 4120150434317. The next prime is 4120150434341. The reversal of 4120150434335 is 5334340510214.
It is not a de Polignac number, because 4120150434335 - 26 = 4120150434271 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4120150434295 and 4120150434304.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 456319601 + ... + 456328629.
It is an arithmetic number, because the mean of its divisors is an integer number (88381612620).
Almost surely, 24120150434335 is an apocalyptic number.
4120150434335 is a deficient number, since it is larger than the sum of its proper divisors (1536272773345).
4120150434335 is a wasteful number, since it uses less digits than its factorization.
4120150434335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10388.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 4120150434335 its reverse (5334340510214), we get a palindrome (9454490944549).
The spelling of 4120150434335 in words is "four trillion, one hundred twenty billion, one hundred fifty million, four hundred thirty-four thousand, three hundred thirty-five".
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