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430113020 = 22553405767
BaseRepresentation
bin11001101000110…
…000000011111100
31002222100000010212
4121220300003330
51340102104040
6110402451552
713441620551
oct3150600374
91088300125
10430113020
11200873307
12100063bb8
136b155b5c
14411a2a28
1527b60d65
hex19a300fc

430113020 has 24 divisors (see below), whose sum is σ = 920281824. Its totient is φ = 168798656.

The previous prime is 430112993. The next prime is 430113023. The reversal of 430113020 is 20311034.

It is a junction number, because it is equal to n+sod(n) for n = 430112986 and 430113004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (430113023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 201824 + ... + 203943.

It is an arithmetic number, because the mean of its divisors is an integer number (38345076).

Almost surely, 2430113020 is an apocalyptic number.

It is an amenable number.

430113020 is an abundant number, since it is smaller than the sum of its proper divisors (490168804).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

430113020 is a wasteful number, since it uses less digits than its factorization.

430113020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 405829 (or 405827 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 14.

The square root of 430113020 is about 20739.1663284714. The cubic root of 430113020 is about 754.8503540963.

Adding to 430113020 its reverse (20311034), we get a palindrome (450424054).

The spelling of 430113020 in words is "four hundred thirty million, one hundred thirteen thousand, twenty".

Divisors: 1 2 4 5 10 20 53 106 212 265 530 1060 405767 811534 1623068 2028835 4057670 8115340 21505651 43011302 86022604 107528255 215056510 430113020