Base | Representation |
---|---|
bin | 110000111001100100001010… |
… | …0001110101111000001000010 |
3 | 2002101221110120110102020102220 |
4 | 1201303020110032233001002 |
5 | 422334123211330412010 |
6 | 4122444144401351510 |
7 | 156412305006026052 |
oct | 14163102416570102 |
9 | 2071843513366386 |
10 | 430124134232130 |
11 | 115061691508638 |
12 | 402a8b32338596 |
13 | 156006bb533960 |
14 | 7830195033562 |
15 | 34ad7b0cea970 |
hex | 18732143af042 |
430124134232130 has 32 divisors (see below), whose sum is σ = 1111705454631744. Its totient is φ = 105876709964736.
The previous prime is 430124134232041. The next prime is 430124134232131. The reversal of 430124134232130 is 31232431421034.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 430124134232091 and 430124134232100.
It is not an unprimeable number, because it can be changed into a prime (430124134232131) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 551441197344 + ... + 551441198123.
It is an arithmetic number, because the mean of its divisors is an integer number (34740795457242).
Almost surely, 2430124134232130 is an apocalyptic number.
430124134232130 is an abundant number, since it is smaller than the sum of its proper divisors (681581320399614).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
430124134232130 is a wasteful number, since it uses less digits than its factorization.
430124134232130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1102882395490.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 430124134232130 its reverse (31232431421034), we get a palindrome (461356565653164).
The spelling of 430124134232130 in words is "four hundred thirty trillion, one hundred twenty-four billion, one hundred thirty-four million, two hundred thirty-two thousand, one hundred thirty".
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