Base | Representation |
---|---|
bin | 101000001001101111… |
… | …100010100000111000 |
3 | 11010021121221221002002 |
4 | 220021233202200320 |
5 | 1201243430130130 |
6 | 31450024000132 |
7 | 3054245362451 |
oct | 501157424070 |
9 | 133247857062 |
10 | 43113130040 |
11 | 17314268792 |
12 | 8432600048 |
13 | 40b1026a46 |
14 | 212dc22128 |
15 | 11c4e75b45 |
hex | a09be2838 |
43113130040 has 32 divisors (see below), whose sum is σ = 97246485360. Its totient is φ = 17202240000.
The previous prime is 43113130019. The next prime is 43113130063. The reversal of 43113130040 is 4003131134.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a junction number, because it is equal to n+sod(n) for n = 43113129994 and 43113130021.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1327886 + ... + 1359965.
Almost surely, 243113130040 is an apocalyptic number.
43113130040 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
43113130040 is an abundant number, since it is smaller than the sum of its proper divisors (54133355320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
43113130040 is a wasteful number, since it uses less digits than its factorization.
43113130040 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2688263 (or 2688259 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 43113130040 its reverse (4003131134), we get a palindrome (47116261174).
The spelling of 43113130040 in words is "forty-three billion, one hundred thirteen million, one hundred thirty thousand, forty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •