4500413 has 4 divisors (see below), whose sum is σ = 4504668. Its totient is φ = 4496160.

The previous prime is 4500409. The next prime is 4500439. The reversal of 4500413 is 3140054.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 1800964 + 2699449 = 1342^2 + 1643^2 .

It is a cyclic number.

It is not a de Polignac number, because 4500413 - 2² = 4500409 is a prime.

It is an Ulam number.

It is a Duffinian number.

It is a plaindrome in base 16.

It is a junction number, because it is equal to n+sod(n) for n = 4500391 and 4500400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4500443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 833 + ... + 3113.

It is an arithmetic number, because the mean of its divisors is an integer number (1126167).

Almost surely, 2^4500413 is an apocalyptic number.

It is an amenable number.

4500413 is a deficient number, since it is larger than the sum of its proper divisors (4255).

4500413 is a wasteful number, since it uses less digits than its factorization.

4500413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4254.

The product of its (nonzero) digits is 240, while the sum is 17.

The square root of 4500413 is about 2121.4176863598. The cubic root of 4500413 is about 165.1014130160.

Adding to 4500413 its reverse (3140054), we get a palindrome (7640467).

It can be divided in two parts, 4500 and 413, that added together give a cube (4913 = 17³).

The spelling of 4500413 in words is "four million, five hundred thousand, four hundred thirteen".