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45999954000 = 243353711132337
BaseRepresentation
bin101010110101110011…
…111001100001010000
311101201211000210002000
4222311303321201100
51223201442012000
633044310354000
73215631105030
oct526563714120
9141654023060
1045999954000
1118565858310
128ab935b900
1344511333c0
1423253a78c0
1512e3611000
hexab5cf9850

45999954000 has 2560 divisors, whose sum is σ = 237104824320. Its totient is φ = 8211456000.

The previous prime is 45999953969. The next prime is 45999954017. The reversal of 45999954000 is 45999954.

45999954000 is a `hidden beast` number, since 4 + 5 + 9 + 9 + 99 + 540 + 0 + 0 = 666.

45999954000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (54).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 511 ways as a sum of consecutive naturals, for example, 1243241982 + ... + 1243242018.

It is an arithmetic number, because the mean of its divisors is an integer number (92619072).

Almost surely, 245999954000 is an apocalyptic number.

45999954000 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 45999954000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (118552412160).

45999954000 is an abundant number, since it is smaller than the sum of its proper divisors (191104870320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

45999954000 is a wasteful number, since it uses less digits than its factorization.

45999954000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 123 (or 101 counting only the distinct ones).

The product of its (nonzero) digits is 2624400, while the sum is 54.

45999954000 divided by its reverse (45999954) gives a cube (1000 = 103).

It can be divided in two parts, 45999 and 954000, that added together give a palindrome (999999).

The spelling of 45999954000 in words is "forty-five billion, nine hundred ninety-nine million, nine hundred fifty-four thousand".