Base | Representation |
---|---|
bin | 101110100100100001… |
… | …111100000011000111 |
3 | 11210001221020012212112 |
4 | 232210201330003013 |
5 | 1304402240003031 |
6 | 34545540411235 |
7 | 3420112330103 |
oct | 564441740307 |
9 | 153057205775 |
10 | 50005000391 |
11 | 1a230578a05 |
12 | 98366a6b1b |
13 | 493bb00a38 |
14 | 25c5272903 |
15 | 147a03162b |
hex | ba487c0c7 |
50005000391 has 4 divisors (see below), whose sum is σ = 50256282000. Its totient is φ = 49753718784.
The previous prime is 50005000343. The next prime is 50005000403. The reversal of 50005000391 is 19300050005.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 19300050005 = 5 ⋅3860010001.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50005000391 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (50005000301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 125640506 + ... + 125640903.
It is an arithmetic number, because the mean of its divisors is an integer number (12564070500).
Almost surely, 250005000391 is an apocalyptic number.
50005000391 is a deficient number, since it is larger than the sum of its proper divisors (251281609).
50005000391 is a wasteful number, since it uses less digits than its factorization.
50005000391 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 251281608.
The product of its (nonzero) digits is 675, while the sum is 23.
Adding to 50005000391 its reverse (19300050005), we get a palindrome (69305050396).
The spelling of 50005000391 in words is "fifty billion, five million, three hundred ninety-one", and thus it is an aban number.
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