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510011211013 is a prime number
BaseRepresentation
bin1110110101111110000…
…10010111110100000101
31210202102120001220222121
413122333002113310011
531324000332223023
61030143530125541
751563360523433
oct7327702276405
91722376056877
10510011211013
1118732703a507
1282a158808b1
133912b262085
141a982a63d53
15d3ee9a7d5d
hex76bf097d05

510011211013 has 2 divisors, whose sum is σ = 510011211014. Its totient is φ = 510011211012.

The previous prime is 510011211011. The next prime is 510011211029. The reversal of 510011211013 is 310112110015.

It is a happy number.

It is an a-pointer prime, because the next prime (510011211029) can be obtained adding 510011211013 to its sum of digits (16).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 378647007649 + 131364203364 = 615343^2 + 362442^2 .

It is a cyclic number.

It is not a de Polignac number, because 510011211013 - 21 = 510011211011 is a prime.

It is a super-2 number, since 2×5100112110132 (a number of 24 digits) contains 22 as substring.

Together with 510011211011, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (510011211011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255005605506 + 255005605507.

It is an arithmetic number, because the mean of its divisors is an integer number (255005605507).

Almost surely, 2510011211013 is an apocalyptic number.

It is an amenable number.

510011211013 is a deficient number, since it is larger than the sum of its proper divisors (1).

510011211013 is an equidigital number, since it uses as much as digits as its factorization.

510011211013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30, while the sum is 16.

Adding to 510011211013 its reverse (310112110015), we get a palindrome (820123321028).

The spelling of 510011211013 in words is "five hundred ten billion, eleven million, two hundred eleven thousand, thirteen".