Base | Representation |
---|---|
bin | 100101001100001000101… |
… | …1001101010001111101110 |
3 | 200002122011111101110022200 |
4 | 1022120101121222033232 |
5 | 1132220422033142200 |
6 | 14512033350322330 |
7 | 1035164565556215 |
oct | 112302131521756 |
9 | 20078144343280 |
10 | 5111303021550 |
11 | 16a0767338a90 |
12 | 6a67310593a6 |
13 | 2b0cbc51652b |
14 | 139561a3607c |
15 | 8ce53e04800 |
hex | 4a61166a3ee |
5111303021550 has 144 divisors (see below), whose sum is σ = 14982111226368. Its totient is φ = 1238992372800.
The previous prime is 5111303021507. The next prime is 5111303021563. The reversal of 5111303021550 is 551203031115.
5111303021550 is a `hidden beast` number, since 51 + 1 + 1 + 30 + 30 + 2 + 1 + 550 = 666.
It is a super-2 number, since 2×51113030215502 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 63928899 + ... + 64008801.
It is an arithmetic number, because the mean of its divisors is an integer number (104042439072).
Almost surely, 25111303021550 is an apocalyptic number.
5111303021550 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 5111303021550, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (7491055613184).
5111303021550 is an abundant number, since it is smaller than the sum of its proper divisors (9870808204818).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5111303021550 is a wasteful number, since it uses less digits than its factorization.
5111303021550 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 92855 (or 92847 counting only the distinct ones).
The product of its (nonzero) digits is 2250, while the sum is 27.
Adding to 5111303021550 its reverse (551203031115), we get a palindrome (5662506052665).
The spelling of 5111303021550 in words is "five trillion, one hundred eleven billion, three hundred three million, twenty-one thousand, five hundred fifty".
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