Base | Representation |
---|---|
bin | 101111100110100101… |
… | …000101010101010111 |
3 | 11212221011100120201200 |
4 | 233212211011111113 |
5 | 1314134424333421 |
6 | 35251523323543 |
7 | 3456426234543 |
oct | 574645052527 |
9 | 155834316650 |
10 | 51113121111 |
11 | 1a74a02a458 |
12 | 9aa58205b3 |
13 | 4a87565a80 |
14 | 268c4c6a23 |
15 | 14e246d726 |
hex | be6945557 |
51113121111 has 48 divisors (see below), whose sum is σ = 88617241440. Its totient is φ = 28045854720.
The previous prime is 51113121109. The next prime is 51113121173. The reversal of 51113121111 is 11112131115.
51113121111 is a `hidden beast` number, since 511 + 131 + 2 + 11 + 11 = 666.
It is not a de Polignac number, because 51113121111 - 21 = 51113121109 is a prime.
It is a super-2 number, since 2×511131211112 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51123121111) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 638470 + ... + 714051.
It is an arithmetic number, because the mean of its divisors is an integer number (1846192530).
Almost surely, 251113121111 is an apocalyptic number.
51113121111 is a gapful number since it is divisible by the number (51) formed by its first and last digit.
51113121111 is a deficient number, since it is larger than the sum of its proper divisors (37504120329).
51113121111 is a wasteful number, since it uses less digits than its factorization.
51113121111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1352576 (or 1352573 counting only the distinct ones).
The product of its digits is 30, while the sum is 18.
Adding to 51113121111 its reverse (11112131115), we get a palindrome (62225252226).
The spelling of 51113121111 in words is "fifty-one billion, one hundred thirteen million, one hundred twenty-one thousand, one hundred eleven".
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