Base | Representation |
---|---|
bin | 100101010110110000100… |
… | …0000001000101110010000 |
3 | 200011211001012000220202220 |
4 | 1022231201000020232100 |
5 | 1133104131004010100 |
6 | 14530325030541040 |
7 | 1036633054244205 |
oct | 112554100105620 |
9 | 20154035026686 |
10 | 5134113344400 |
11 | 16aa402156177 |
12 | 6ab038207780 |
13 | 2b31b61c3ba1 |
14 | 13a6c726bcac |
15 | 8d83b748aa0 |
hex | 4ab61008b90 |
5134113344400 has 60 divisors (see below), whose sum is σ = 16446276417072. Its totient is φ = 1369096891520.
The previous prime is 5134113344303. The next prime is 5134113344401. The reversal of 5134113344400 is 44433114315.
It is a tau number, because it is divible by the number of its divisors (60).
It is a super-2 number, since 2×51341133444002 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (5134113344401) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2139212694 + ... + 2139215093.
Almost surely, 25134113344400 is an apocalyptic number.
5134113344400 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
5134113344400 is an abundant number, since it is smaller than the sum of its proper divisors (11312163072672).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5134113344400 is a wasteful number, since it uses less digits than its factorization.
5134113344400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4278427808 (or 4278427797 counting only the distinct ones).
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 5134113344400 its reverse (44433114315), we get a palindrome (5178546458715).
The spelling of 5134113344400 in words is "five trillion, one hundred thirty-four billion, one hundred thirteen million, three hundred forty-four thousand, four hundred".
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