Search a number
-
+
515322531120000 = 2735419234913449
BaseRepresentation
bin111010100101011101110000…
…0011010011000001110000000
32111120121100112020010112120010
41311022323200122120032000
51020021021020431320000
65023555522544344520
7213354552500504352
oct16512734032301600
92446540466115503
10515322531120000
1113a21a07042857a
1249968b61015140
13191709245c3b26
149137a5a58b0d2
153e89ac57b3d50
hex1d4aee0698380

515322531120000 has 640 divisors, whose sum is σ = 1878793218720000. Its totient is φ = 124526426112000.

The previous prime is 515322531119933. The next prime is 515322531120013. The reversal of 515322531120000 is 21135223515.

It is a tau number, because it is divible by the number of its divisors (640).

It is a super-2 number, since 2×5153225311200002 (a number of 30 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a self number, because there is not a number n which added to its sum of digits gives 515322531120000.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 102423276 + ... + 107336724.

It is an arithmetic number, because the mean of its divisors is an integer number (2935614404250).

Almost surely, 2515322531120000 is an apocalyptic number.

515322531120000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 515322531120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (939396609360000).

515322531120000 is an abundant number, since it is smaller than the sum of its proper divisors (1363470687600000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

515322531120000 is a wasteful number, since it uses less digits than its factorization.

515322531120000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4913528 (or 4913501 counting only the distinct ones).

The product of its (nonzero) digits is 9000, while the sum is 30.

Adding to 515322531120000 its reverse (21135223515), we get a palindrome (515343666343515).

The spelling of 515322531120000 in words is "five hundred fifteen trillion, three hundred twenty-two billion, five hundred thirty-one million, one hundred twenty thousand".