Base | Representation |
---|---|
bin | 110001011000110111… |
… | …000011000110110000 |
3 | 12001212210010010110112 |
4 | 301120313003012300 |
5 | 1332101242330300 |
6 | 40210054120452 |
7 | 3555100146653 |
oct | 613067030660 |
9 | 161783103415 |
10 | 53030433200 |
11 | 2054332a3a8 |
12 | a33b950128 |
13 | 500184b474 |
14 | 27d0db989a |
15 | 15a594ae35 |
hex | c58dc31b0 |
53030433200 has 60 divisors (see below), whose sum is σ = 130513110168. Its totient is φ = 20694796800.
The previous prime is 53030433133. The next prime is 53030433217. The reversal of 53030433200 is 233403035.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1600382 + ... + 1633181.
Almost surely, 253030433200 is an apocalyptic number.
53030433200 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
53030433200 is an abundant number, since it is smaller than the sum of its proper divisors (77482676968).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53030433200 is a wasteful number, since it uses less digits than its factorization.
53030433200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3233622 (or 3233611 counting only the distinct ones).
The product of its (nonzero) digits is 3240, while the sum is 23.
Adding to 53030433200 its reverse (233403035), we get a palindrome (53263836235).
The spelling of 53030433200 in words is "fifty-three billion, thirty million, four hundred thirty-three thousand, two hundred".
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