| Base | Representation |
|---|---|
| bin | 1001111001001111… |
| … | …01011010100010100 |
| 3 | 111201012110121212220 |
| 4 | 10330213223110110 |
| 5 | 41334333020200 |
| 6 | 2235034342340 |
| 7 | 245431160154 |
| oct | 47447532424 |
| 9 | 14635417786 |
| 10 | 5312001300 |
| 11 | 2286539221 |
| 12 | 1042b8a9b0 |
| 13 | 66869c148 |
| 14 | 3856ba764 |
| 15 | 2115364a0 |
| hex | 13c9eb514 |
5312001300 has 144 divisors (see below), whose sum is σ = 15607542720. Its totient is φ = 1394749440.
The previous prime is 5312001283. The next prime is 5312001301. The reversal of 5312001300 is 31002135.
It is a happy number.
It is a super-2 number, since 2×53120013002 = 56434715622403380000, which contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 5312001300.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5312001301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 8060371 + ... + 8061029.
Almost surely, 25312001300 is an apocalyptic number.
5312001300 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 5312001300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (7803771360).
5312001300 is an abundant number, since it is smaller than the sum of its proper divisors (10295541420).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5312001300 is a wasteful number, since it uses less digits than its factorization.
5312001300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1050 (or 1043 counting only the distinct ones).
The product of its (nonzero) digits is 90, while the sum is 15.
The square root of 5312001300 is about 72883.4775515000. The cubic root of 5312001300 is about 1744.8284109186.
Adding to 5312001300 its reverse (31002135), we get a palindrome (5343003435).
The spelling of 5312001300 in words is "five billion, three hundred twelve million, one thousand, three hundred".
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