Base | Representation |
---|---|
bin | 110001100110011011… |
… | …010110010111101100 |
3 | 12002110122102102021012 |
4 | 301212123112113230 |
5 | 1333033030144400 |
6 | 40244424524352 |
7 | 3563532660560 |
oct | 614633262754 |
9 | 162418372235 |
10 | 53258053100 |
11 | 2064a86761a |
12 | a3a40206b8 |
13 | 5039a562b5 |
14 | 281330b6a0 |
15 | 15ba90dd35 |
hex | c666d65ec |
53258053100 has 72 divisors (see below), whose sum is σ = 132410046048. Its totient is φ = 18214272000.
The previous prime is 53258053091. The next prime is 53258053133. The reversal of 53258053100 is 135085235.
It is a super-2 number, since 2×532580531002 (a number of 22 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 185834 + ... + 375566.
Almost surely, 253258053100 is an apocalyptic number.
53258053100 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 53258053100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (66205023024).
53258053100 is an abundant number, since it is smaller than the sum of its proper divisors (79151992948).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53258053100 is a wasteful number, since it uses less digits than its factorization.
53258053100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 190155 (or 190148 counting only the distinct ones).
The product of its (nonzero) digits is 18000, while the sum is 32.
The spelling of 53258053100 in words is "fifty-three billion, two hundred fifty-eight million, fifty-three thousand, one hundred".
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