Base | Representation |
---|---|
bin | 110010100111000111… |
… | …110000000001101001 |
3 | 12012021021202111102120 |
4 | 302213013300001221 |
5 | 1342243404344340 |
6 | 40544240221453 |
7 | 3632452366434 |
oct | 624707600151 |
9 | 165237674376 |
10 | 54343434345 |
11 | 210574a7612 |
12 | a64760a889 |
13 | 5180889015 |
14 | 28b752281b |
15 | 1630d584d0 |
hex | ca71f0069 |
54343434345 has 64 divisors (see below), whose sum is σ = 96931399680. Its totient is φ = 25871712768.
The previous prime is 54343434337. The next prime is 54343434349.
54343434345 is nontrivially palindromic in base 10.
54343434345 is an esthetic number in base 10, because in such base its adjacent digits differ by 1.
It is not a de Polignac number, because 54343434345 - 23 = 54343434337 is a prime.
It is an alternating number because its digits alternate between odd and even.
It is a junction number, because it is equal to n+sod(n) for n = 54343434297 and 54343434306.
It is not an unprimeable number, because it can be changed into a prime (54343434349) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 377317 + ... + 501053.
It is an arithmetic number, because the mean of its divisors is an integer number (1514553120).
Almost surely, 254343434345 is an apocalyptic number.
It is an amenable number.
54343434345 is a deficient number, since it is larger than the sum of its proper divisors (42587965335).
54343434345 is a wasteful number, since it uses less digits than its factorization.
54343434345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 123854.
The product of its digits is 2073600, while the sum is 42.
The spelling of 54343434345 in words is "fifty-four billion, three hundred forty-three million, four hundred thirty-four thousand, three hundred forty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.091 sec. • engine limits •