Base | Representation |
---|---|
bin | 11001000011101010110010… |
… | …10001001101011010100000 |
3 | 21020002122221112221000202211 |
4 | 30201311121101031122200 |
5 | 24210241121034432000 |
6 | 313105201340251504 |
7 | 14414650556451241 |
oct | 1441653121153240 |
9 | 236078845830684 |
10 | 55101633124000 |
11 | 16614520446a01 |
12 | 621b095540b94 |
13 | 24990a5759628 |
14 | d86d0cc88cc8 |
15 | 6584beb5e7ba |
hex | 321d5944d6a0 |
55101633124000 has 96 divisors (see below), whose sum is σ = 136725156286992. Its totient is φ = 21822428800000.
The previous prime is 55101633123991. The next prime is 55101633124007. The reversal of 55101633124000 is 42133610155.
It can be written as a sum of positive squares in 8 ways, for example, as 16014179139984 + 39087453984016 = 4001772^2 + 6251996^2 .
It is not an unprimeable number, because it can be changed into a prime (55101633124007) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 67791091 + ... + 68599090.
Almost surely, 255101633124000 is an apocalyptic number.
55101633124000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
55101633124000 is an abundant number, since it is smaller than the sum of its proper divisors (81623523162992).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
55101633124000 is a wasteful number, since it uses less digits than its factorization.
55101633124000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 136390307 (or 136390289 counting only the distinct ones).
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 55101633124000 its reverse (42133610155), we get a palindrome (55143766734155).
The spelling of 55101633124000 in words is "fifty-five trillion, one hundred one billion, six hundred thirty-three million, one hundred twenty-four thousand".
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