Base | Representation |
---|---|
bin | 11001101001011111010010… |
… | …01001011000001010111000 |
3 | 21101200220011112010110221122 |
4 | 30310233221021120022320 |
5 | 24343034002020112100 |
6 | 315542153050324412 |
7 | 14610563336223236 |
oct | 1464575111301270 |
9 | 241626145113848 |
10 | 56401127113400 |
11 | 16a75646976913 |
12 | 63aaabb429708 |
13 | 25617aca75bc4 |
14 | dcdb87155956 |
15 | 67c1c9430985 |
hex | 334be92582b8 |
56401127113400 has 48 divisors (see below), whose sum is σ = 131890612645800. Its totient is φ = 22430043601280.
The previous prime is 56401127113367. The next prime is 56401127113403. The reversal of 56401127113400 is 431172110465.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (56401127113403) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 815010590 + ... + 815079789.
Almost surely, 256401127113400 is an apocalyptic number.
56401127113400 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
56401127113400 is an abundant number, since it is smaller than the sum of its proper divisors (75489485532400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
56401127113400 is a wasteful number, since it uses less digits than its factorization.
56401127113400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1630090568 (or 1630090559 counting only the distinct ones).
The product of its (nonzero) digits is 20160, while the sum is 35.
Adding to 56401127113400 its reverse (431172110465), we get a palindrome (56832299223865).
The spelling of 56401127113400 in words is "fifty-six trillion, four hundred one billion, one hundred twenty-seven million, one hundred thirteen thousand, four hundred".
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