Base | Representation |
---|---|
bin | 101110100101100001… |
… | …1010100111101111101 |
3 | 100120020012022212101120 |
4 | 1131023003110331331 |
5 | 3114342103130300 |
6 | 113543113301153 |
7 | 10141111652064 |
oct | 1351303247575 |
9 | 316205285346 |
10 | 100043411325 |
11 | 39478996730 |
12 | 174804047b9 |
13 | 95847cbc10 |
14 | 4bb0b211db |
15 | 2907e623a0 |
hex | 174b0d4f7d |
100043411325 has 96 divisors (see below), whose sum is σ = 196248189312. Its totient is φ = 44330880000.
The previous prime is 100043411291. The next prime is 100043411339. The reversal of 100043411325 is 523114340001.
It is a happy number.
It is not a de Polignac number, because 100043411325 - 26 = 100043411261 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 100043411295 and 100043411304.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1037047 + ... + 1129403.
It is an arithmetic number, because the mean of its divisors is an integer number (2044251972).
Almost surely, 2100043411325 is an apocalyptic number.
100043411325 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
100043411325 is a deficient number, since it is larger than the sum of its proper divisors (96204777987).
100043411325 is a wasteful number, since it uses less digits than its factorization.
100043411325 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 92495 (or 92490 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 100043411325 its reverse (523114340001), we get a palindrome (623157751326).
The spelling of 100043411325 in words is "one hundred billion, forty-three million, four hundred eleven thousand, three hundred twenty-five".
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