Base | Representation |
---|---|
bin | 10110110000111101001001… |
… | …110000100101011101111111 |
3 | 111010111111100222100011100002 |
4 | 112300331021300211131333 |
5 | 101110341224322011312 |
6 | 552535015322224515 |
7 | 30042343112111252 |
oct | 2660751160453577 |
9 | 433444328304302 |
10 | 100121220110207 |
11 | 299a119766313a |
12 | b2901b605513b |
13 | 43b35100460ca |
14 | 1aa1c70201099 |
15 | b895b19344c2 |
hex | 5b0f49c2577f |
100121220110207 has 2 divisors, whose sum is σ = 100121220110208. Its totient is φ = 100121220110206.
The previous prime is 100121220110183. The next prime is 100121220110209. The reversal of 100121220110207 is 702011022121001.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100121220110207 - 212 = 100121220106111 is a prime.
Together with 100121220110209, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100121220110209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060610055103 + 50060610055104.
It is an arithmetic number, because the mean of its divisors is an integer number (50060610055104).
Almost surely, 2100121220110207 is an apocalyptic number.
100121220110207 is a deficient number, since it is larger than the sum of its proper divisors (1).
100121220110207 is an equidigital number, since it uses as much as digits as its factorization.
100121220110207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 20.
Adding to 100121220110207 its reverse (702011022121001), we get a palindrome (802132242231208).
The spelling of 100121220110207 in words is "one hundred trillion, one hundred twenty-one billion, two hundred twenty million, one hundred ten thousand, two hundred seven".
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