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100132321303040 = 295133008783693
BaseRepresentation
bin10110110001000111011111…
…011100010001101000000000
3111010112120000122012012001012
4112301013133130101220000
5101111031443223144130
6552544053043300052
730043215160515035
oct2661073734215000
9433476018165035
10100132321303040
11299a5973a27674
12b29239397a628
1343b458bc11170
141aa26046d338c
15b89a11311995
hex5b11df711a00

100132321303040 has 80 divisors (see below), whose sum is σ = 258550800392808. Its totient is φ = 36971934007296.

The previous prime is 100132321303037. The next prime is 100132321303043. The reversal of 100132321303040 is 40303123231001.

It is an interprime number because it is at equal distance from previous prime (100132321303037) and next prime (100132321303043).

It can be written as a sum of positive squares in 4 ways, for example, as 86856733532416 + 13275587770624 = 9319696^2 + 3643568^2 .

It is a tau number, because it is divible by the number of its divisors (80).

It is a junction number, because it is equal to n+sod(n) for n = 100132321302997 and 100132321303015.

It is not an unprimeable number, because it can be changed into a prime (100132321303043) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1504358567 + ... + 1504425126.

Almost surely, 2100132321303040 is an apocalyptic number.

100132321303040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

100132321303040 is an abundant number, since it is smaller than the sum of its proper divisors (158418479089768).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

100132321303040 is an equidigital number, since it uses as much as digits as its factorization.

100132321303040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3008783729 (or 3008783713 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 100132321303040 its reverse (40303123231001), we get a palindrome (140435444534041).

The spelling of 100132321303040 in words is "one hundred trillion, one hundred thirty-two billion, three hundred twenty-one million, three hundred three thousand, forty".

Divisors: 1 2 4 5 8 10 13 16 20 26 32 40 52 64 65 80 104 128 130 160 208 256 260 320 416 512 520 640 832 1040 1280 1664 2080 2560 3328 4160 6656 8320 16640 33280 3008783693 6017567386 12035134772 15043918465 24070269544 30087836930 39114188009 48140539088 60175673860 78228376018 96281078176 120351347720 156456752036 192562156352 195570940045 240702695440 312913504072 385124312704 391141880090 481405390880 625827008144 770248625408 782283760180 962810781760 1251654016288 1540497250816 1564567520360 1925621563520 2503308032576 3129135040720 3851243127040 5006616065152 6258270081440 7702486254080 10013232130304 12516540162880 20026464260608 25033080325760 50066160651520 100132321303040