Base | Representation |
---|---|
bin | 101111000101000100… |
… | …1111111000101100000 |
3 | 100122221222110220110120 |
4 | 1132022021333011200 |
5 | 3124024120340222 |
6 | 114240133200240 |
7 | 10206255565113 |
oct | 1361211770540 |
9 | 318858426416 |
10 | 101102121312 |
11 | 3997156a165 |
12 | 17716a90080 |
13 | 96c2c53b2a |
14 | 4c7159257a |
15 | 296ad8e15c |
hex | 178a27f160 |
101102121312 has 48 divisors (see below), whose sum is σ = 273954143232. Its totient is φ = 32613586560.
The previous prime is 101102121287. The next prime is 101102121331. The reversal of 101102121312 is 213121201101.
It is a tau number, because it is divible by the number of its divisors (48).
It is a junction number, because it is equal to n+sod(n) for n = 101102121291 and 101102121300.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16983268 + ... + 16989219.
It is an arithmetic number, because the mean of its divisors is an integer number (5707377984).
Almost surely, 2101102121312 is an apocalyptic number.
101102121312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
101102121312 is an abundant number, since it is smaller than the sum of its proper divisors (172852021920).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
101102121312 is a wasteful number, since it uses less digits than its factorization.
101102121312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33972531 (or 33972523 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 101102121312 its reverse (213121201101), we get a palindrome (314223322413).
The spelling of 101102121312 in words is "one hundred one billion, one hundred two million, one hundred twenty-one thousand, three hundred twelve".
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