10112213120 has 64 divisors (see below), whose sum is σ = 25225611840. Its totient is φ = 3869015040.

The previous prime is 10112213101. The next prime is 10112213129. The reversal of 10112213120 is 2131221101.

It is a tau number, because it is divible by the number of its divisors (64).

It is a junction number, because it is equal to n+sod(n) for n = 10112213095 and 10112213104.

It is not an unprimeable number, because it can be changed into a prime (10112213129) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 328766 + ... + 358205.

It is an arithmetic number, because the mean of its divisors is an integer number (394150185).

Almost surely, 2^10112213120 is an apocalyptic number.

10112213120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

10112213120 is an abundant number, since it is smaller than the sum of its proper divisors (15113398720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10112213120 is an equidigital number, since it uses as much as digits as its factorization.

10112213120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 687013 (or 687001 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 10112213120 its reverse (2131221101), we get a palindrome (12243434221).

The spelling of 10112213120 in words is "ten billion, one hundred twelve million, two hundred thirteen thousand, one hundred twenty".