Base | Representation |
---|---|
bin | 10010110110011010… |
… | …01010111111011101 |
3 | 222010021210001202021 |
4 | 21123031022333131 |
5 | 131211222123031 |
6 | 4352113100141 |
7 | 505533356644 |
oct | 113315127735 |
9 | 28107701667 |
10 | 10120114141 |
11 | 43235a45a5 |
12 | 1b65257651 |
13 | c53854327 |
14 | 6c00ac35b |
15 | 3e36d7511 |
hex | 25b34afdd |
10120114141 has 2 divisors, whose sum is σ = 10120114142. Its totient is φ = 10120114140.
The previous prime is 10120114139. The next prime is 10120114157. The reversal of 10120114141 is 14141102101.
It is an a-pointer prime, because the next prime (10120114157) can be obtained adding 10120114141 to its sum of digits (16).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8541641241 + 1578472900 = 92421^2 + 39730^2 .
It is a cyclic number.
It is not a de Polignac number, because 10120114141 - 21 = 10120114139 is a prime.
Together with 10120114139, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10120114111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060057070 + 5060057071.
It is an arithmetic number, because the mean of its divisors is an integer number (5060057071).
Almost surely, 210120114141 is an apocalyptic number.
It is an amenable number.
10120114141 is a deficient number, since it is larger than the sum of its proper divisors (1).
10120114141 is an equidigital number, since it uses as much as digits as its factorization.
10120114141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32, while the sum is 16.
Adding to 10120114141 its reverse (14141102101), we get a palindrome (24261216242).
The spelling of 10120114141 in words is "ten billion, one hundred twenty million, one hundred fourteen thousand, one hundred forty-one".
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