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1012012012181 is a prime number
BaseRepresentation
bin11101011101000001001…
…11011101001010010101
310120202011212010212110002
432232200213131022111
5113040100033342211
62052524545341045
7133054413112502
oct16564047351225
93522155125402
101012012012181
11360212441495
12144174937785
1374580a77a61
1436da58b04a9
151b4d10ab03b
hexeba09dd295

1012012012181 has 2 divisors, whose sum is σ = 1012012012182. Its totient is φ = 1012012012180.

The previous prime is 1012012012153. The next prime is 1012012012183. The reversal of 1012012012181 is 1812102102101.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 901485685156 + 110526327025 = 949466^2 + 332455^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1012012012181 is a prime.

It is a super-2 number, since 2×10120120121812 (a number of 25 digits) contains 22 as substring.

Together with 1012012012183, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1012012012183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506006006090 + 506006006091.

It is an arithmetic number, because the mean of its divisors is an integer number (506006006091).

Almost surely, 21012012012181 is an apocalyptic number.

It is an amenable number.

1012012012181 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012012012181 is an equidigital number, since it uses as much as digits as its factorization.

1012012012181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64, while the sum is 20.

Adding to 1012012012181 its reverse (1812102102101), we get a palindrome (2824114114282).

The spelling of 1012012012181 in words is "one trillion, twelve billion, twelve million, twelve thousand, one hundred eighty-one".