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101211224111 is a prime number
BaseRepresentation
bin101111001000010101…
…0001011100000101111
3100200020120202220100222
41132100222023200233
53124240033132421
6114255031441555
710212052132064
oct1362052134057
9320216686328
10101211224111
1139a18108768
12177475262bb
13970c7339ba
144c81c72c6b
152975740cab
hex1790a8b82f

101211224111 has 2 divisors, whose sum is σ = 101211224112. Its totient is φ = 101211224110.

The previous prime is 101211224077. The next prime is 101211224113. The reversal of 101211224111 is 111422112101.

It is a strong prime.

It is an emirp because it is prime and its reverse (111422112101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101211224111 - 218 = 101210961967 is a prime.

Together with 101211224113, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 101211224111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101211224113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50605612055 + 50605612056.

It is an arithmetic number, because the mean of its divisors is an integer number (50605612056).

Almost surely, 2101211224111 is an apocalyptic number.

101211224111 is a deficient number, since it is larger than the sum of its proper divisors (1).

101211224111 is an equidigital number, since it uses as much as digits as its factorization.

101211224111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32, while the sum is 17.

Adding to 101211224111 its reverse (111422112101), we get a palindrome (212633336212).

The spelling of 101211224111 in words is "one hundred one billion, two hundred eleven million, two hundred twenty-four thousand, one hundred eleven".