| Base | Representation |
|---|---|
| bin | 101111001000101001… |
| … | …1110010100110000100 |
| 3 | 100200021100022002022120 |
| 4 | 1132101103302212010 |
| 5 | 3124300331211400 |
| 6 | 114300101325540 |
| 7 | 10212243632565 |
| oct | 1362123624604 |
| 9 | 320240262276 |
| 10 | 101222132100 |
| 11 | 39a23289031 |
| 12 | 1774b1068b0 |
| 13 | 9711a8292b |
| 14 | 4c834b216c |
| 15 | 2976697ca0 |
| hex | 17914f2984 |
101222132100 has 144 divisors (see below), whose sum is σ = 300992193600. Its totient is φ = 26244933120.
The previous prime is 101222132093. The next prime is 101222132107. The reversal of 101222132100 is 1231222101.
It is an interprime number because it is at equal distance from previous prime (101222132093) and next prime (101222132107).
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 101222132100.
It is not an unprimeable number, because it can be changed into a prime (101222132107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 25183891 + ... + 25187909.
Almost surely, 2101222132100 is an apocalyptic number.
101222132100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 101222132100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (150496096800).
101222132100 is an abundant number, since it is smaller than the sum of its proper divisors (199770061500).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
101222132100 is a wasteful number, since it uses less digits than its factorization.
101222132100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6342 (or 6335 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 101222132100 its reverse (1231222101), we get a palindrome (102453354201).
Subtracting from 101222132100 its reverse (1231222101), we obtain a palindrome (99990909999).
The spelling of 101222132100 in words is "one hundred one billion, two hundred twenty-two million, one hundred thirty-two thousand, one hundred".
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