101433060 has 108 divisors (see below), whose sum is σ = 319911228. Its totient is φ = 27013824.

The previous prime is 101433053. The next prime is 101433083. The reversal of 101433060 is 60334101.

It can be written as a sum of positive squares in 2 ways, for example, as 19131876 + 82301184 = 4374^2 + 9072^2 .

It is a tau number, because it is divible by the number of its divisors (108).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 130834 + ... + 131606.

It is an arithmetic number, because the mean of its divisors is an integer number (2962141).

Almost surely, 2^101433060 is an apocalyptic number.

101433060 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 101433060, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (159955614).

101433060 is an abundant number, since it is smaller than the sum of its proper divisors (218478168).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101433060 is an frugal number, since it uses more digits than its factorization.

101433060 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 806 (or 783 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

The square root of 101433060 is about 10071.3981154555. The cubic root of 101433060 is about 466.3656005961.

Adding to 101433060 its reverse (60334101), we get a palindrome (161767161).

It can be divided in two parts, 10143 and 3060, that added together give a triangular number (13203 = T₁₆₂).

The spelling of 101433060 in words is "one hundred one million, four hundred thirty-three thousand, sixty".