Base | Representation |
---|---|
bin | 10111100010110110100100… |
… | …101101111110000100011000 |
3 | 111120122021222121100002022210 |
4 | 113202312210231332010120 |
5 | 102033031131243202100 |
6 | 1004122134550315120 |
7 | 30545151516534132 |
oct | 2742664455760430 |
9 | 446567877302283 |
10 | 103550130053400 |
11 | 2aaa33aa961448 |
12 | b744861058aa0 |
13 | 45a197379a4b4 |
14 | 1b7dbd2a34052 |
15 | be889ab2ac50 |
hex | 5e2da4b7e118 |
103550130053400 has 48 divisors (see below), whose sum is σ = 321005403167400. Its totient is φ = 27613368014080.
The previous prime is 103550130053399. The next prime is 103550130053429. The reversal of 103550130053400 is 4350031055301.
It is a super-3 number, since 3×1035501300534003 (a number of 43 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 86291774445 + ... + 86291775644.
Almost surely, 2103550130053400 is an apocalyptic number.
103550130053400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
103550130053400 is an abundant number, since it is smaller than the sum of its proper divisors (217455273114000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
103550130053400 is a wasteful number, since it uses less digits than its factorization.
103550130053400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 172583550108 (or 172583550099 counting only the distinct ones).
The product of its (nonzero) digits is 13500, while the sum is 30.
The spelling of 103550130053400 in words is "one hundred three trillion, five hundred fifty billion, one hundred thirty million, fifty-three thousand, four hundred".
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