Base | Representation |
---|---|
bin | 110000001110000110… |
… | …0000000010001110100 |
3 | 100220021201120221100121 |
4 | 1200130030000101310 |
5 | 3144033320432040 |
6 | 115323213221324 |
7 | 10324055350132 |
oct | 1403414002164 |
9 | 326251527317 |
10 | 103552124020 |
11 | 3aa09524494 |
12 | 1809b491844 |
13 | 99c36c9187 |
14 | 5024b0a752 |
15 | 2a60ee0c4a |
hex | 181c300474 |
103552124020 has 96 divisors (see below), whose sum is σ = 225426862080. Its totient is φ = 39939070080.
The previous prime is 103552124009. The next prime is 103552124153. The reversal of 103552124020 is 20421255301.
103552124020 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×1035521240203 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 11998947 + ... + 12007573.
It is an arithmetic number, because the mean of its divisors is an integer number (2348196480).
Almost surely, 2103552124020 is an apocalyptic number.
103552124020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
103552124020 is an abundant number, since it is smaller than the sum of its proper divisors (121874738060).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
103552124020 is a wasteful number, since it uses less digits than its factorization.
103552124020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8893 (or 8891 counting only the distinct ones).
The product of its (nonzero) digits is 2400, while the sum is 25.
Adding to 103552124020 its reverse (20421255301), we get a palindrome (123973379321).
The spelling of 103552124020 in words is "one hundred three billion, five hundred fifty-two million, one hundred twenty-four thousand, twenty".
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