Base | Representation |
---|---|
bin | 111101111000111… |
… | …111011011100010 |
3 | 2200100211122111021 |
4 | 331320333123202 |
5 | 4111304200200 |
6 | 251011240054 |
7 | 34505554423 |
oct | 7570773342 |
9 | 2610748437 |
10 | 1038350050 |
11 | 493137841 |
12 | 24b8a902a |
13 | 137176a1a |
14 | 9bc9164a |
15 | 6125941a |
hex | 3de3f6e2 |
1038350050 has 24 divisors (see below), whose sum is σ = 1938483072. Its totient is φ = 413802000.
The previous prime is 1038350041. The next prime is 1038350059. The reversal of 1038350050 is 500538301.
It is a happy number.
It is an interprime number because it is at equal distance from previous prime (1038350041) and next prime (1038350059).
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a junction number, because it is equal to n+sod(n) for n = 1038349997 and 1038350024.
It is not an unprimeable number, because it can be changed into a prime (1038350059) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 24766 + ... + 51865.
It is an arithmetic number, because the mean of its divisors is an integer number (80770128).
Almost surely, 21038350050 is an apocalyptic number.
1038350050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1038350050 is a deficient number, since it is larger than the sum of its proper divisors (900133022).
1038350050 is a wasteful number, since it uses less digits than its factorization.
1038350050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 76914 (or 76909 counting only the distinct ones).
The product of its (nonzero) digits is 1800, while the sum is 25.
The square root of 1038350050 is about 32223.4394501891. The cubic root of 1038350050 is about 1012.6233310113.
Adding to 1038350050 its reverse (500538301), we get a palindrome (1538888351).
The spelling of 1038350050 in words is "one billion, thirty-eight million, three hundred fifty thousand, fifty".
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