Base | Representation |
---|---|
bin | 110001000010100001… |
… | …0110111000000000000 |
3 | 101001211022212002022121 |
4 | 1202011002313000000 |
5 | 3211134200200100 |
6 | 120213535214024 |
7 | 10415466400306 |
oct | 1420502670000 |
9 | 331738762277 |
10 | 105311334400 |
11 | 40731559268 |
12 | 184b0677314 |
13 | 9c1400716c |
14 | 5150606276 |
15 | 2b1568d51a |
hex | 18850b7000 |
105311334400 has 156 divisors (see below), whose sum is σ = 267224429032. Its totient is φ = 41143173120.
The previous prime is 105311334347. The next prime is 105311334407. The reversal of 105311334400 is 4433113501.
It is a super-2 number, since 2×1053113344002 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (105311334407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4391242 + ... + 4415158.
Almost surely, 2105311334400 is an apocalyptic number.
105311334400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 105311334400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (133612214516).
105311334400 is an abundant number, since it is smaller than the sum of its proper divisors (161913094632).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
105311334400 is an equidigital number, since it uses as much as digits as its factorization.
105311334400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23994 (or 23967 counting only the distinct ones).
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 105311334400 its reverse (4433113501), we get a palindrome (109744447901).
The spelling of 105311334400 in words is "one hundred five billion, three hundred eleven million, three hundred thirty-four thousand, four hundred".
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