Base | Representation |
---|---|
bin | 10100011111011101… |
… | …10010010110011100 |
3 | 1001101200222001012200 |
4 | 22033232302112130 |
5 | 140012320410330 |
6 | 5015352531500 |
7 | 536423600313 |
oct | 121756622634 |
9 | 31350861180 |
10 | 11001341340 |
11 | 4735a74640 |
12 | 21703b0b90 |
13 | 10642a7042 |
14 | 76513d27a |
15 | 445c56a60 |
hex | 28fbb259c |
11001341340 has 72 divisors (see below), whose sum is σ = 36404445168. Its totient is φ = 2666991360.
The previous prime is 11001341303. The next prime is 11001341357. The reversal of 11001341340 is 4314310011.
It is a super-2 number, since 2×110013413402 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2776137 + ... + 2780096.
It is an arithmetic number, because the mean of its divisors is an integer number (505617294).
Almost surely, 211001341340 is an apocalyptic number.
11001341340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11001341340 is an abundant number, since it is smaller than the sum of its proper divisors (25403103828).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11001341340 is a wasteful number, since it uses less digits than its factorization.
11001341340 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5556259 (or 5556254 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 11001341340 its reverse (4314310011), we get a palindrome (15315651351).
The spelling of 11001341340 in words is "eleven billion, one million, three hundred forty-one thousand, three hundred forty".
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